The scores of an eighth-grade math test have a normal distribution with a mean u = 83 and a standard deviation o = 5. IfDin's test score was 92, which expression would she write to find the Z-score of her test score?92-83O2- 835O z: 83-92O z- 92-83092

Answer:[tex]z=\frac{92-83}{5}[/tex]Step-by-step explanation:* Lets explain how to find the z-score - If the data have normal distribution with a mean μ and a standard  deviation σ and we need to find the z-score for score x,then  [tex]z=\frac{x-u}{o}[/tex]* Lets solve the problem- The scores of an eighth-grade math test have a normal distribution- The mean is 83- The standard deviation is 5- Din's test score was 92- We need to find z-score of Din's test score∵ x = 92∵ μ = 83∵ σ = 5∴ [tex]z=\frac{92-83}{5}[/tex]